What Is Standard Form In (X+1) (X-3)=6

What is standard form in (x+1) (x-3)=6

Answer: $\boxed{\boxed{x^{2} -2x - 9 = 0}}$

Step-by-step explanation:

Standard Form of Quadratic Equation

$ax^{2} + bx + c = 0$

Solution:

Use FOIL Method

$(x+1) (x-3)=6\\ x^{2} -3x + x -3 = 6$

Transpose 6 and combine terms.

$x^{2} -3x + x -3 - 6 = 0\\ \boxed{\boxed{x^{2} -2x - 9 = 0}}$

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